1Z0-051 practice test

Passing 1Z0-051 test will help you in achieving Oracle OCA DBA 11g certification. You also have to pass this test if you want to pursue the more advanced OCP certification and OCA PL/SQL Developer certification. This 1Z0-051 exam is appropriate for you if you have experience in Oracle Databases and you want to work as a Database Administrator (DBA).

1Z0-051 Oracle Database 11g: SQL Fundamentals I
Exam available online
Displaying Data from Multiple Tables 
Write SELECT statements to access data from more than one table using equijoins and nonequijoins
Join a table to itself by using a self-join
View data that generally does not meet a join condition by using outer joins
Generate a Cartesian product of all rows from two or more tables

Using Subqueries to Solve Queries 
Define subqueries
Describe the types of problems that the subqueries can solve
List the types of subqueries
Write single-row and multiple-row subqueries

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The 1Z0-051 is known as Oracle Database 11g: SQL Fundamentals I. The Oracle’s 1Z0-051 exam is designed to measure your skills and knowledge of the installation, management and maintenance of Oracle11g databases. Oracle’s 1Z0-051 tests the candidate’s expertise in Retrieving Data Using the SQL SELECT Statement; Restricting and Sorting Data; Reporting Aggregated Data Using the Group Functions; Using Conversion Functions and Conditional Expressions; Displaying Data from Multiple Tables; Using Subqueries to Solve Queries; Using the Set Operators; Manipulating Data; Using DDL Statements to Create and Manage Tables etc.

Free 1z0-047 PDF Demo Download
You need to produce a report where each customer's credit limit has been incremented by $1000. In the output, the customer's last name should have the heading Name and the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?
A.SELECT cust_last_name Name, cust_credit_limit + 1000"New Credit Limit"FROM customers;
B.SELECT cust_last_name AS Name, cust_credit_limit + 1000AS New Credit LimitFROM customers;
C.SELECT cust_last_name AS "Name", cust_credit_limit + 1000AS "New Credit Limit"FROM customers;
D.SELECT INITCAP(cust_last_name) "Name", cust_credit_limit + 1000INITCAP("NEW CREDIT LIMIT")FROM customers;
Answer: C

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